cos(-61π/12)=多少

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热心网友

cos(-61π/12）=cos(-5π-π/12)=-cos(π/12)=-(√6+√2)/4

望采纳。。。。。。。。

热心网友

cos(-61π/12）=cos(-5π-π/12)=-cos(π/12)=-(√6+√2)/4

望采纳。。。。。。。。

热心网友

cos(-61π/12)=cos(-6π+11π/12)=cos(11π/12)=cos(3π/12+8π/12)=cos(π/4+2π/3)=cos(π/4)cos(2π/3)-sin(π/4)sin(2π/3)=√2/2*(-1/2-√3/2)=-√2/4-√6/4

热心网友

cos(-61π/12)=cos(-6π+11π/12)=cos(11π/12)=cos(3π/12+8π/12)=cos(π/4+2π/3)=cos(π/4)cos(2π/3)-sin(π/4)sin(2π/3)=√2/2*(-1/2-√3/2)=-√2/4-√6/4

热心网友

cos(-61π/12）
=cos(61π/12）
=cos[(72π-11π)/12]
=cos11π/12
=cos[π-π/12]
=-cosπ/12
=-(√6+√2)/4

热心网友

－（更号6 更号2）/4

热心网友

cos(-61π/12）=cos(-5π-π/12)=-cos(π/12)=-(√6+√2)/4

望采纳。。。。。。。。

热心网友

cos(-61π/12)=cos(-6π+11π/12)=cos(11π/12)=cos(3π/12+8π/12)=cos(π/4+2π/3)=cos(π/4)cos(2π/3)-sin(π/4)sin(2π/3)=√2/2*(-1/2-√3/2)=-√2/4-√6/4

热心网友

cos(-61π/12）
=cos(61π/12）
=cos[(72π-11π)/12]
=cos11π/12
=cos[π-π/12]
=-cosπ/12
=-(√6+√2)/4

热心网友

cos(-61π/12）
=cos(61π/12）
=cos[(72π-11π)/12]
=cos11π/12
=cos[π-π/12]
=-cosπ/12
=-(√6+√2)/4

热心网友

cos(-61π/12）=cos(-5π-π/12)=-cos(π/12)=-(√6+√2)/4

望采纳。。。。。。。。

热心网友

－（更号6 更号2）/4

热心网友

cos(-61π/12)=cos(-6π+11π/12)=cos(11π/12)=cos(3π/12+8π/12)=cos(π/4+2π/3)=cos(π/4)cos(2π/3)-sin(π/4)sin(2π/3)=√2/2*(-1/2-√3/2)=-√2/4-√6/4

热心网友

－（更号6 更号2）/4

热心网友

cos(-61π/12）
=cos(61π/12）
=cos[(72π-11π)/12]
=cos11π/12
=cos[π-π/12]
=-cosπ/12
=-(√6+√2)/4

热心网友

－（更号6 更号2）/4

热心网友

cos(-61π/12）=cos(-5π-π/12)=-cos(π/12)=-(√6+√2)/4

望采纳。。。。。。。。

热心网友

cos(-61π/12)=cos(-6π+11π/12)=cos(11π/12)=cos(3π/12+8π/12)=cos(π/4+2π/3)=cos(π/4)cos(2π/3)-sin(π/4)sin(2π/3)=√2/2*(-1/2-√3/2)=-√2/4-√6/4

热心网友

cos(-61π/12）
=cos(61π/12）
=cos[(72π-11π)/12]
=cos11π/12
=cos[π-π/12]
=-cosπ/12
=-(√6+√2)/4

热心网友

－（更号6 更号2）/4