发布网友 发布时间:2022-04-23 00:43
共4个回答
懂视网 时间:2022-04-18 18:27
这篇文章主要介绍了Python实现的根据文件名查找数据文件功能,涉及Python针对文件与目录的遍历、查询等相关操作技巧,需要的朋友可以参考下本文实例讲述了Python实现的根据文件名查找数据文件功能。分享给大家供大家参考,具体如下:
#-*- coding: UTF-8 -*- import os import shutil AllFiles=[] NameFiles=[] def findFie(filePath): pathDir = os.listdir(filePath) for allDir in pathDir: # print(allDir) AllFiles.append(allDir) #pass #filepath = 'C:UsersIBM_ADMINDesktopcognosdatastage71&727171sns' #copyfile = 'C:UsersIBM_ADMINDesktopcognosdatastage71&7271mtp' filepath = 'C:UsersIBM_ADMINDesktopcognosdatastage71&727272sns' copyfile = 'C:UsersIBM_ADMINDesktopcognosdatastage71&7272mtp' shutil.rmtree(copyfile) os.mkdir(copyfile) findFie(filepath) def readFile(): readFile = open('./jobname') i = 0 for eachLine in readFile: i= i + 1 #print(eachLine) NameFiles.append(eachLine.replace(' ','')) # 去掉换行符 readFile() #字符串比较 def doTheCompare(): for x in NameFiles: print(x) for y in AllFiles: if x == y : copyFrom = os.path.join(filepath,x) copyTo = os.path.join(copyfile,x) shutil.copyfile(copyFrom,copyTo) else: pass #print ("file not find under sns process,thanks .please check with wumi.") doTheCompare()
附:这里再补充一个更为简单的文件搜索功能示例:
# -*- coding:utf-8 -*- import os def search(path=".", name="1"): for item in os.listdir(path): item_path = os.path.join(path, item) if os.path.isdir(item_path): search(item_path, name) elif os.path.isfile(item_path): if name in item: print(item_path) if __name__ == "__main__": search(path=r"D:360Downloads",name="dll")
热心网友 时间:2022-04-18 15:35
若不包含子目录的遍历:
import glob否则可以:
import os热心网友 时间:2022-04-18 16:53
glob模块或者遍历目录加endswith方法
热心网友 时间:2022-04-18 18:28
glob模块