发布网友 发布时间:2022-04-23 19:11
共1个回答
热心网友 时间:2023-10-14 09:19
C'=0
(x^n)' = nx^(n-1)
(a^x)' = a^x * lna
(e^x)' = e^x
(loga(x))' = 1/(xlna)
(lnx)' = 1/x
(sinx)' = cosx
(cosx)' = -sinx
(tanx)' = (secx)^2
(cotx)' = -(cscx)^2
(secx)' = secxtanx
(cscx)' = -cscxcotx